初一数学化简求值答案

1、已知A,B是方程x^2+2x-5=0的两个实数根,

求(A^2+2AB+2A)(B^2+2AB+2B)的值.

由A,B是方程x^2+2x-5=0的两个实数根得：

AB=-5，A+B=-2

A^2+2AB+2A)(B^2+2AB+2B)

=AB（A+2B+2）（B+2A+2）

=-5（-2+B+2）（-2+A+2）

=-5AB

=25

2、1/2(x+y+z)方+1/2(x-y-z)(x-y+z)-z(x+y),其中x-y=6,xy=21.要详细步骤

化简得：

1/2(x+y+z)方+1/2(x-y-z)(x-y+z)-z(x+y)=

1/2[(x+y)方+2z(x+y)+z方]+1/2[(x-y)方-z方]-z(x+y)=

1/2(x+y)方+1/2(x-y)方=x方＋y方

由x-y=6,xy=21得，x方＋y方＝（x-y）方＋2xy＝78

3、a^2-ab+2b^2=3 求2ab-2a^2-4b^2-7的值

2ab-2a^2-4b^2-7

=2(ab-a^2-2b^2)-7

=-2(a^2-ab+2b^2)-7

=(-2)*3-7

=-6-7=-13

4、若A=2x^2+3xy-2x-3,B=-x^2+xy+2,且3A+6B的值与x无关，求y的值

3A+6B=6x^2+9xy-6x-9-6x^2+6xy+12

=15xy-6x+3

=x(15y-6)+3

5、9x+6x^2 -3(x-2/3x^2).其中x=-2

9x+6x² -3(x-2/3x²)

=9x+6x²-3x+2x²

=8x²+6x

=8×(-2)²+6×(-2)

=32-12

=20